pub type AnyMap = Map<dyn Any>;Expand description
The most common type of Map: just using Any; [Map]<dyn [Any]>.
Why is this a separate type alias rather than a default value for Map<A>?
Map::default() doesn’t seem to be happy to infer that it should go with the default
value. It’s a bit sad, really. Ah well, I guess this approach will do.
Aliased Type§
pub struct AnyMap { /* private fields */ }